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m= 1,5 kg
c=1 kkal/kg°C -> 1000 Kal/kg°c
T2=80
t1=30
ditanya Q..?
Q = m × c × ΔT
= 1,5 kg × 1000 kal/kg°C × (80-30)°C
= 1,5 × 1000 ×50 kal
= 75000 kal
= 75 kkal