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Q=5 x 0.11 x 100
Q=55
c = 0,11 kal/kg °C
Δt = t₁ - to
= 140 - 40
= 100°C
Ditanyakan : Q
Penyelesaian : Q = m . c . Δt
= 5 . 0,11 . 100
= 55 kal