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Verified answer
Diketm=0,02 kg
Q=184 joule
c=460 j/kg°C
ditanya=Δt..?
jawab
Δt= Q/ m.c
= 184 J/ 0,02 kg . 460 J/kg°C
= 184 / 9,2 °C
= 184 × 10/92 °C
= 20°C
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