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T₁ = 10°C
Q = 2 kJ = 2000 J
c = 130 J/Kg°C
ditanya : T₂ = .... ?
dijawab :
Q = m . c . (T₂ - T₁)
2000 = 1 . 130 (T₂ - 10)
2000 / 130 = T₂ - 10
15.38 + 10 = T₂
T₂ = 25,38°C