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massa baja =200 gr
Δt baja =14°c
massa alkohol=200gr
Δt alkohol =3°c
c alkohol =2100
c baja = ?
Qbaja=Qalkohol
m×c×Δt=m×c×Δt
200×c×14 =200×2100×3
2800×c=1260000
c=1260000/2800
c=450
jadi kalor jenis baja 450 j/kg°c