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t2-t1=Q/m.c
t2-35=63000/1,5.4200
t2-35=10
t2=35+10
t2=45 derajat celcius
dit : Δt ?
jwb :
Q = m x C x Δt
63000 = 1,5 x 4200 x (t₂ - t₁)
63000 = 6300 (t₂ - 35)
63000 = 6300 t₂ - 220500
63000 + 220500 = 6300 t₂
283500 = 6300 t₂
t₂ = 45°C