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W=150kJ=150000J
m=2kg
cw=2090j/kg
t=20stopni
szukane
Q=?
cw=Q/m*t
cw*m*t=Q
2090*2*20=Q
83600=Q
m - masa = 2 kg
Δt = 20°C
Cw = 2090 J/kg°C
Q - ilość wydzielonego ciepla = ?
J - iloścv ciepla = ?
Q = CwmΔt = 2090 razy 2 razy 20 = 83600 J