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m = 2 kg
c air = 4200 J/Kg.K
ΔT = 100 - 0 = 100°C
Ditanyakan Q . . ?
Penyelesaian :
Q = m c ΔT
= 2 . 4200 . 100
= 840000 J
= 840 KJ
Q=m.Cair.delta T
=2.4200.100
=840000 J
=840KJ
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