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m= 3 kg
t₁= 30°C
Q= 15000 J
C= 450 J/kg°C
Dit:
t₂=..?
Penye:
t₂= Δt+t₁
Δt= Q/(m.C)
Δt= 15000/(3×450)
Δt= 15000/1350
Δt= 11,11 °C
t₂= 11,11+30
t₂= 41,11 °C
m = 3 kg
to = 30°C
Q = 15000 J
C = 450 J/kg°C
Dit:
t₂.....?
Dij :
t₂ = Δt + t₁
Δt = Q / ( m . C )
Δt = 15000 / ( 3 × 450 )
Δt = 15000 / 1350
Δt = 11,11 °C
t₂ = 11,11 + 30
t₂ = 41,11 °C
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