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T1=25°C
T2=85°C
c=4200J/kg
Dit=Q?
Jawab=
Q=m.c.(T2-T1)
=2.4200.(85-25)
=8400.60
=504.000J
m = 2kg
t1 = 25°C
t2 = 85°C
∆t = 60°C
c = 4200J/kg°C
dijawab
Q = m.c.∆t
= 2 kg . 4200J/kg°C . 60°C
= 8400J/°C . 60°C
= 504000 J