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- Kalor
m = 2 kg
Q = 180 kJ = 180.000 J menerima kalor
c = 900 J/(kg °C)
t₁ = 20 °C
t₂ = ___ ?
menerima kalor, suhu naik
suhu akhir
Q = m c Δt
180.000 = 2 · 900 · (t₂ - 20)
180.000 = 1800 · (t₂ - 20)
100 = t₂ - 20
t₂ = 120 °C ← jawaban
massa alumunium (m) = 2kg
suhu awal (T1) = 20°C
kalor yg diterima (Q) = 180kJ = 180000J
kalor jenis (c) = 900J/kg°C
ditanya:
suhu akhir(T2)???
jawab
Q = m × c × (T2 - T1)
(T2 - T1) = Q / (m × c)
(T2 - T1) = 180000/(2×900)
(T2 - T1) = 180000/1800
(T2 - T1) = 100
T2 - 20 = 100
T2 = 100+20
T2 = 120°C
smoga membantu