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m= 10 kg
Q= 11 kkal --> 11×4200= 46200 J
C= 0,11 kkal/kg°C --> 0,11×4200= 462 J/kg°C
Dit:
Δt=..?
Penye:
Δt= Q/(m.C)
Δt= 46200/(10×462)
Δt= 46200/4620
Δt= 10°C
Q = 11 kkal ⇒ 11 × 4200= 46200 J
C = 0,11 kkal/kg°C ⇒ 0,11×4200= 462 J/kg°C
Ditanya = Δt..?
Jawb = Δt = Q/(m.C)
=