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c = 1 kkal/KgC
Q =1 kkal
m = 400 g = 0,4 Kg
Ditanyakn : ΔT ?
Dijawab :
Q = mx c x ΔT
1 = 0,4 x 1 x ΔT
1 = 0,4 ΔT
ΔT = 1/0,4
ΔT = 2,5 C
Jadi kenaikan suhu = 2,5⁰C