Suatu balok tembaga bermassa 3kg dipanaskan dari 26 derajad celcius hingga mencapai suhu 81derajad celcius apabila kalor yg diperlukan 64.350 joule kalor jenis tembaga ..........j/kg derajad celcius
Zuhh
Dik : m = 3 kg T0 = 26 C T = 81 C Q = 64.350 J dit : c ?
dijawab : Q = m x c x ΔT 64.350 = 3 x c x (81-26) 64.350 = 3 x c x 55 64.350 = 165 x c c = 64.350/165 c = 390 J/KgC
m = 3 kg
T0 = 26 C
T = 81 C
Q = 64.350 J
dit : c ?
dijawab :
Q = m x c x ΔT
64.350 = 3 x c x (81-26)
64.350 = 3 x c x 55
64.350 = 165 x c
c = 64.350/165
c = 390 J/KgC