Bejana tembaga (Ctembaga=390 J/kg 'C ) massanya 0,5 kg mula-mula bersuhu 20'C kemudian diberikan kalor sebanyak 7800 J maka suhu bejana tersebut menjadi .........
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7800 = 195 x ( TAkhir - TAwal)
40 = TAkhir - 20
TAkhir = 60
c Tembaga = 390 J/Kg°C
Massa = 0,5 Kg
ΔT = (T - 20)°C
Q = 7800 Joule
Q = m . c . ΔT
7800 = 0,5 Kg . 390 J/Kg°C . (T - 20)°C
T - 20 =
T - 20 = =
T - 20 = 40°C
T = 40 + 20 = 60 °C
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