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diket :
Q = 159 600 J
m = 500 gram = 0,5 kg
t2 = 100'C
c = 4200 J/kg'C
ditanya : t1
Q = m c delta t = 159 600
0,5 . 4200. (100 - t1 ) = 159 600
2100 (100 - t1) = 159 600
100 - t1 = 159 600/2100 = 76
t1 = 100 - 76 = 24'C
m = 500 gr
= 0,5 kg
t₁ = 100°C
c = 4200 J/kg °C
Ditanyakan : to (t₁ - Δt)
Penyelesaian : Δt = Q : (m . c)
= 159600 : 0,5 . (4200)
= 159600 : 2100
= 76°C
to = t₁ - Δt
= 100 - 76
= 24°C