Kerucut dgn jari jari 5cm dan volume 314 cm2 jika phi 3,14 maka tentukan a. tinggi kerucut b. panjang garis pelukis c. luas selimut kerucut d. luas permukaan kerucutt
wee dii jawab ya yg tw buat jalan nya ya please !!!
anaharyanto
A. = V x 3,14 x 5 x 5 x t = 314 x 78,5 x t = 314 = = 4 t = 4 : t = 4 x t = 12
b. s = = = = = 13
c. = 3,14 x 5 x 13 = 204,1
d. πr(r+s) = 3,14 x 5 (5 + 13) = 15,7 x 18 = 282,6
maaf klo salah :)
0 votes Thanks 4
unocitruslord
V = 1/3.pi.r^2.t 314 = 1/3.3,14.25.t t = 12 cm garis pelukis = 13 cm (Pake phytagoras 5, 12, 13) L selimut = pi.r.s = 3,14.5.13 = 204,1 cm^2 Lp = pi.r(r+s) = 3,14.5 (5+13) = 282,6 cm^2
x 3,14 x 5 x 5 x t = 314
x 78,5 x t = 314
=
= 4
t = 4 :
t = 4 x
t = 12
b. s =
=
=
=
= 13
c.
= 3,14 x 5 x 13
= 204,1
d. πr(r+s)
= 3,14 x 5 (5 + 13)
= 15,7 x 18
= 282,6
maaf klo salah :)
314 = 1/3.3,14.25.t
t = 12 cm
garis pelukis = 13 cm (Pake phytagoras 5, 12, 13)
L selimut = pi.r.s = 3,14.5.13 = 204,1 cm^2
Lp = pi.r(r+s) = 3,14.5 (5+13) = 282,6 cm^2