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Verified answer
Y = 2px²y' = 4px
garis g melalui (a, b)
gradien garis g
m = y'
m = 4px
m = 4pa
tegak lurus dengan garis g
m1 . m2 = -1
4pa . m2 = -1
m2 = -1/4pa
melalui titik (c, d)
Persamaan garis
(y - y1) = m(x - x1)
(y - d) = -1/4pa(x - c)
4pa(y - d) = -(x - c)
4pa(y - d) + (x - c) = 0
Jawaban A