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1/y=b
2a+3b=12
3a-b=7 kali 3
2a+3b=12
9a-3b=21
11a=33
a=3
b=2
1/x=3
x=1/3
1/y=2
y=1/2
(1/3,1/2)
1/x = A
1/y = B
sehingga :
2/x +3/y = 12
2·(1/x) + 3·(1/y) =12
2A + 3B =12..........(1)
3/x - 1/y = 7
3·(1/x) - 1/y = 7
3A - B = 7........(2)
2A + 3B = 12 × 1 2A + 3B = 12
3A - B = 7 x 3 9A - 3B = 21
---------------------+
11A = 33
A = 33/11 = 3
Substitusi A = 3 ke persamaan (2), diperoleh :
3A - B = 7
3(3) - B = 7
9 - B = 7
B = 2
Sehingga diperoleh :
A = 3 B = 2
1/x = 3 1/y = 2
x = 1/3 y = 1/2
Jawabannya adalah : C. (1/3, 1/2)