kerjakan dengan benar.... Question from @pottahpottah424

August 2022 2 6 Report

kerjakan dengan benar

JΟY

Bentuk rasional dari ${\sf{\dfrac{6}{\sqrt{\sf5}-\sqrt{\sf3}}={\boldsymbol{\textsf{\textbf{3}}\sqrt{\textsf{\textbf{5}}}+\textsf{\textbf{3}}\sqrt{\textsf{\textbf{3}}}}}}}$

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$\begin{aligned}{\sf{\frac{6}{\sqrt{\sf5}-\sqrt{\sf3}}}}&={\sf{\frac{6}{\sqrt{\sf5}-\sqrt{\sf3}}\times\frac{\sqrt{\sf5}+\sqrt{\sf3}}{\sqrt{\sf5}+\sqrt{\sf3}}}}\\&={\sf{\frac{6\left(\sqrt{\sf5}+\sqrt{\sf3}\right)}{\left(\sqrt{\sf5}-\sqrt{\sf3}\right)\left(\sqrt{\sf5}+\sqrt{\sf3}\right)}}}\\&={\sf{\frac{6\left(\sqrt{\sf5}+\sqrt{\sf3}\right)}{5-3}}}\\&={\sf{\frac{6\sqrt{5}+6\sqrt{\sf3}}{2}}}\\&={\sf{3\sqrt{5}+3\sqrt{\sf3}}}\end{aligned}$

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BNP999

Penjelasan dengan langkah-langkah:

= 6/(√5 - √3)

= 6/(√5 - √3) . (√5+√3)/(√5+√3)

= 6(√5+√3)/((√5)²-(√3)²)

= 6(√5+√3)/(5-3)

= 6(√5+√3)/2

= 3(√5 +√3)

= 3√5+3√3

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