19. U3 = 3 U5 = 1/3 berati r = 3, 1, 1/3 => Karena tiap kenaikannya r = 1/3 artinya r = 1/3 Suku pertama U1 = 3 : 1/9 . 1/9 Karena kenaikannya Ada 2 deret Dari U3 ke U1 U1 = 3 x 9 U1 = 27
U9 = 27 x 1/3^9-1 27 x 1/6561 = 27/6561 1/243
18 . tiap detet nurun 2 . berati r = 1/2 Suki pertama = 8 Sn = ½ n [ 2a + ( n – 1 ) b ] 1/2 9 ( 2 . 8 + ( 9 - 1 ) 1/2 ) 9/2 ( 16 + 4 ) 9/2 . 20 180/2 90
Verified answer
Yok lanjut...nomor 13 itu yg diketahui u5 sama u brapa?
Verified answer
19.U3 = 3
U5 = 1/3
berati r = 3, 1, 1/3 => Karena tiap kenaikannya r = 1/3 artinya r = 1/3
Suku pertama
U1 = 3 : 1/9 . 1/9 Karena kenaikannya Ada 2 deret Dari U3 ke U1
U1 = 3 x 9
U1 = 27
U9 = 27 x 1/3^9-1
27 x 1/6561
= 27/6561
1/243
18 . tiap detet nurun 2 . berati r = 1/2
Suki pertama = 8
Sn = ½ n [ 2a + ( n – 1 ) b ]
1/2 9 ( 2 . 8 + ( 9 - 1 ) 1/2 )
9/2 ( 16 + 4 )
9/2 . 20
180/2
90