Kerjain no. 10 - 14. Pake jalan. Pliss .... Question from @fria12345681

October 2018 1 80 Report

Kerjain no. 10 - 14. Pake jalan. Pliss ....

BringinSuroboyo Nomor 10

$$\begin{align} \log x^4-3\log x+\log\frac{1}{x}&=\log x^4-\log x^3+\log x^{-1}\\&=\log(x^4:x^3\times x^{-1})\\&=\log x^{4-3+(-1)}\\&=\log x^0\\&=\log1\\&=\boxed0\ \bold{(a.)} \end$

Nomor 11

$$\begin{align} \log x+\log5&=\log x^2-\log14\\\log5x&=\log\frac{x^2}{14}\\5x&=\frac{x^2}{14}\\x^2&=5x\times14\\x^2&=70x\\x^2-70x&=0\\x(x-70)&=0\\x&=\boxed{0\ $atau$\ 70}\ \bold{(d.)} \end$

Nomor 12

$$\begin{align} ^5\log49\times{^7}\log25&={^5}\log7^2\times{^7}\log5^2\\&=2\times2\times{^5}\log7\times{^7}\log5\\&=2\times2\\&=\boxed4\ \bold{(c.)} \end$

Nomor 13

$$\begin{align} ^a\log\frac{1}{b}\times{^b}\log\frac{1}{c^2}\times{^c}\log\frac{1}{a^3}&={^a}\log b^{-1}\times{^b}\log c^{-2}\times{^c}\log a^{-3}\\&=-1\times-2\times-3\times{^a}\log b\times{^b}\log c\times{^c}\log a\\&=-1\times-2\times-3\\&=\boxed{-6}\ \bold{(a.)} \end$

Nomor 14

$$\begin{align} \left(2^{^2\log6}\right)\left(3^{^9\log5}\right)\left(5^{^{\frac{1}{5}}\log2}\right)&=6\left(3^{^{3^2}\log5}\right)\left(5^{^{5^{-1}}\log2}\right)\\&=6\times5^{\frac{1}{2}}\times2^{-1}\\&=6\times\sqrt5\times\frac{1}{2}\\&=\boxed{3\sqrt5}\ \bold{(d.)} \end$

2 votes Thanks 1

fria12345681 Yang no. 11 maksudnya gimana ?

BringinSuroboyo Kerjakan saja ~~: )

fria12345681 Makasih banyak, ya, Mas.

BringinSuroboyo Sama-sama

fria12345681 Mas, boleh bantuan saya ngerjain soal ?