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40=2(p+l)
20=p+l
Lmaks=p.l=9.11=99cm²
p : l =pxl
19:1=19
18;2=36
17;3=51
16;4=64
15;5=75
14;6=84
13;7=91
12;8=96
11;9=99
maka agar luasnya maksimum ukuran p dan l adalah 11;9
Semog membantu ^^