Luas maksimum
L' = 0
-6x + 12 = 0
-6x = -12
x = 2
p = 3x + 6
= 3(2) + 6
= 6 + 6
= 12 cm
semoga membantu
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Luas maksimum
L' = 0
-6x + 12 = 0
-6x = -12
x = 2
p = 3x + 6
= 3(2) + 6
= 6 + 6
= 12 cm
semoga membantu