Question

Keliling sebidang kebun 280 meter . Jika panjang kebun = 1 1 X lebarnya , berapa cm² luas kebun tersebut?
~~~~dengan cara nya~~~~
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3

Answer 1

P = 1 1/3 l = 4/3 l
K = 2p + 2l
280 = 2(4/3l) + 2l
280 = 8/3l + 6/3l
280 = 14/3 l
l      = 280 x 3 / 14
       = 60 meter

maka p = 4/3 l = 4/3 x 60 = 240/3 = 80 meter

L = p x l = 80 x 60 = 4800 m²
Jadi luasnya 4800 m²
      

Answer 2

K = 280 m
p = 1 1/3 lebar

K = 2 X (panjang+lebar)
280 = 2 X (1 1/3 lebar + lebar)
280 = 2 X (4/3 lebar + lebar)
280 = 2 X (7/3 lebar)
280 = 14/3 lebar
280X3 = 14 lebar
840 = 14 lebar
lebar = 840/14
lebar = 60 m

panjang = 1 1/3 lebar
p = 4/3 X 60 = 80

L = panjang X lebar
L = 80 X 60
Luas = 4.800 m²