Kelarutan X(OH) 2 mempunyai pH =9 Hasil kali kelarutan Ksp dari X(OH) adalah.............
a. 10^-10
b. 5 x 10^-11
c. 10^-15
d. 5 x 10^-16
e. 10^-18
bantu jawab pakai caranya yaaaaaa
a. 10^-10
b. 5 x 10^-11
c. 10^-15
d. 5 x 10^-16
e. 10^-18
bantu jawab pakai caranya yaaaaaa
fatihahalhusna
![X(OH)_2\rightarrow X^{2+}+2OH^-\\~~~~~~S~~~~~~~~~~S~~~~~~~~2S\\\\{[OH^-]}=2S\rightarrow S=\frac{1}{2}[OH^-]\\\\pH=9\rightarrow pOH=5\rightarrow [OH^-]=10^{-5}\\\\S=\frac{1}{2}\times10^{-5}=5\times10^{-6}\ M](https://tex.z-dn.net/?f=X%28OH%29_2%5Crightarrow+X%5E%7B2%2B%7D%2B2OH%5E-%5C%5C%7E%7E%7E%7E%7E%7ES%7E%7E%7E%7E%7E%7E%7E%7E%7E%7ES%7E%7E%7E%7E%7E%7E%7E%7E2S%5C%5C%5C%5C%7B%5BOH%5E-%5D%7D%3D2S%5Crightarrow+S%3D%5Cfrac%7B1%7D%7B2%7D%5BOH%5E-%5D%5C%5C%5C%5CpH%3D9%5Crightarrow+pOH%3D5%5Crightarrow+%5BOH%5E-%5D%3D10%5E%7B-5%7D%5C%5C%5C%5CS%3D%5Cfrac%7B1%7D%7B2%7D%5Ctimes10%5E%7B-5%7D%3D5%5Ctimes10%5E%7B-6%7D%5C+M "X(OH)_2\rightarrow X^{2+}+2OH^-\\~~~~~~S~~~~~~~~~~S~~~~~~~~2S\\\\{[OH^-]}=2S\rightarrow S=\frac{1}{2}[OH^-]\\\\pH=9\rightarrow pOH=5\rightarrow [OH^-]=10^{-5}\\\\S=\frac{1}{2}\times10^{-5}=5\times10^{-6}\ M")
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amsap
trus yg di ksp itu angka 4 nya dikemanain? koq langsung 5x10^-16?
fatihahalhusna
4x125x10^-18=500x10^-18=5x10^-16
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