BaCl2=>Ba(2+) + 2Cl(-)
S=[Ba(2+)][Cl(-)]^2
=(1/2x10^-5)(1x10^-5)^2
=5x10^-6
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BaCl2=>Ba(2+) + 2Cl(-)
S=[Ba(2+)][Cl(-)]^2
=(1/2x10^-5)(1x10^-5)^2
=5x10^-6