Question

Kelarutan AgCl dalam air adalah 10^-5 molL^-1. tentukan kelarutan AgCl dalam larutan CaCl2 0,05 M !

Answer 1

AgCl=[Ag⁺][Cl⁻]
       =s.s
       =s²
       =(10⁻⁵)²
       =10⁻¹°

CaCl₂=[Ca⁺]    [2Cl⁻]
0.05 = 0.05      2x0.05=0.1

Ksp AgCl = [Ag⁺]  [Cl⁻]
10⁻¹°        = s x 10⁻¹
s=10⁻⁹

Answer 2

Ksp AgCl = s^2 = (1x10^-5)^2 = 1x10^-10
AgCl -> Ag^+ + Cl^-
    s        s         s
CaCl2 -> Ca^2+ + 2 CL^-
0,05     : 0,05   : 0,1
Ksp AgCl = [Ag^+] [Cl^-]
1x10^-10 = [Ag^+] [0,1]
1x10^-10 = s . 1x10^-1
s = 1x10^-9