Kedalam 100 ml 0,1 larutan asam asetat ( Ka=10 pangkat min 5 ) ditambahkan sejumlah garam natrium asetat (Mr=82) hingga PH larutan naik menjadi 5. maka massa natrium asetat yg ditambahkan adalah ... gr
fatihahalhusna
![mol\ CH_3COOH=\frac{100}{1000}\times0,1=0,01\ M\\\\pH=5\rightarrow [H^+]=10^{-5}\\\\\displaystyle {[H^+]}=K_a\times\frac{mol\ CH_3COOH}{mol\ CH_3COONa}\\\\10^{-5}=10^{-5}\times\frac{0,01}{mol\ CH_3COONa}\\\\mol\ CH_3COONa=0,01\ M\\\\\text{Jadi massa CH3COONa}=0,01\times82=\boxed{\boxed{\bold{0,82\ gram}}}](https://tex.z-dn.net/?f=mol%5C+CH_3COOH%3D%5Cfrac%7B100%7D%7B1000%7D%5Ctimes0%2C1%3D0%2C01%5C+M%5C%5C%5C%5CpH%3D5%5Crightarrow+%5BH%5E%2B%5D%3D10%5E%7B-5%7D%5C%5C%5C%5C%5Cdisplaystyle+%7B%5BH%5E%2B%5D%7D%3DK_a%5Ctimes%5Cfrac%7Bmol%5C+CH_3COOH%7D%7Bmol%5C+CH_3COONa%7D%5C%5C%5C%5C10%5E%7B-5%7D%3D10%5E%7B-5%7D%5Ctimes%5Cfrac%7B0%2C01%7D%7Bmol%5C+CH_3COONa%7D%5C%5C%5C%5Cmol%5C+CH_3COONa%3D0%2C01%5C++M%5C%5C%5C%5C%5Ctext%7BJadi+massa+CH3COONa%7D%3D0%2C01%5Ctimes82%3D%5Cboxed%7B%5Cboxed%7B%5Cbold%7B0%2C82%5C+gram%7D%7D%7D "mol\ CH_3COOH=\frac{100}{1000}\times0,1=0,01\ M\\\\pH=5\rightarrow [H^+]=10^{-5}\\\\\displaystyle {[H^+]}=K_a\times\frac{mol\ CH_3COOH}{mol\ CH_3COONa}\\\\10^{-5}=10^{-5}\times\frac{0,01}{mol\ CH_3COONa}\\\\mol\ CH_3COONa=0,01\ M\\\\\text{Jadi massa CH3COONa}=0,01\times82=\boxed{\boxed{\bold{0,82\ gram}}}")
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