Question

Kedalam 10 mL 0,1 M H2C2O4 dimasukkan 20 mL 0,1 NaOH, ,bila diketahui harga ke asam alsolat = 2,4.10-², pH larutannya adalah?

Answer 1

H2C2O4 = M × v = 0,1 × 10 = 1 mol
NaOH = M × v = 0,1 × 20 = 2 mol
H+ = Ka × Mol besar-Mol kecil/Mol kecil
=2,4×10^-2 × 2-1/1
=2,4×10^-2
PH = 2-log2,4