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NH₄⁺ + H₂O → NH₄OH + H⁺
b. Harga Kb NH₄OH :
mol NH₄Cl = massa/Mr = 1,07/53,5
mol NH₄Cl = 0,02 mol
M NH₄Cl = mol/Volume
M NH₄Cl = 0,02/0,1
M NH₄Cl = 0,2 Molar
pH = 5 - log 1,05
maka :
[H⁺] = 1,05 x 10⁻⁵
pakai rumus hidrolisis :
[H⁺] = √Kw/Kb x M garam
1,05 x 10⁻⁵ = √10⁻¹⁴/Kb x 0,2
1,05 x 10⁻⁵ = √2 x 10⁻¹⁵/Kb
1,1025 x 10⁻¹⁰ = 2 x 10⁻¹⁵/Kb
. . . . . . .2 x 10⁻¹⁵
Kb = ____________
. . . . . 1,1025 x 10⁻¹⁰
Kb = 1,82 x 10⁻⁵ ☜ Jawaban ✔
Ok?