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panjang kawat = 20 m = 2000 cm
ukuran Rangka = 6 x 4 x 2
maka :
Rangka = 4 x (p+l+t)
= 4 x (6+4+2)
= 4 x 12
= 48 cm
jadi banya Rangka y dibuat = 2000/48 = 41 buah,
dan tersisa kawat sepanjang = 2000 - 1968 = 32 cm
4(6+4+2)=4*12=48
bagi panjang kawat dengan jumlah panjang rusuk
2000÷48=41.67
jadi ada 41 balok