Kawan" tlong bantu jawab ya☺ 1. kalor jenis besi 460J\kg°C. Bila suhu besi bermassa 5 kg bertambah sebesar 40°C , kapasitas kalornya sebesar... 2. Untuk memanaskan 100 gram air agar suhunya naik 15°C diperlukan kalor sebanyak .... (kalor jenis air = 4.200J\kg°C)
whongaliemno.1) diketahui : m = 5 kg c = 460J\kg°C. Δt = 40°C ditanyakan : C Q = m x c x Δt = 5 x 460 x 40 = 9200 Joule C = Q /Δt = 9200 / 40 = 230 Joule/°C. no.2) diketahui : m = 100 gr = 0,1 kg c = 4200 J\kg°C. Δt = 15°C ditanya : Q Q = m x c x Δt = 0,1 x 4200 x 15 = 6300 Joule
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1) Diketahui = m = 5 kg c = 460J\kg°C. Δt = 40°C Ditanyakan = C..? Jawab => Q = m x c x Δt = 5 x 460 x 40 = 9200 Joule => C = Q /Δt = 9200 / 40 = 230 Joule/°C. ========================================================= 2) Diketahui = m = 100 gr = 0,1 kg c = 4200 J\kg°C. Δt = 15°C Ditanya = Q..? Jawab => Q = m x c x Δt = 0,1 x 4200 x 15 = 6300 Joule
c = 460J\kg°C.
Δt = 40°C
ditanyakan : C
Q = m x c x Δt
= 5 x 460 x 40
= 9200 Joule
C = Q /Δt
= 9200 / 40
= 230 Joule/°C.
no.2) diketahui : m = 100 gr = 0,1 kg
c = 4200 J\kg°C.
Δt = 15°C
ditanya : Q
Q = m x c x Δt
= 0,1 x 4200 x 15
= 6300 Joule
c = 460J\kg°C.
Δt = 40°C
Ditanyakan = C..?
Jawab => Q = m x c x Δt
= 5 x 460 x 40
= 9200 Joule
=> C = Q /Δt
= 9200 / 40
= 230 Joule/°C.
=========================================================
2) Diketahui = m = 100 gr = 0,1 kg
c = 4200 J\kg°C.
Δt = 15°C
Ditanya = Q..?
Jawab => Q = m x c x Δt
= 0,1 x 4200 x 15
= 6300 Joule