kawałek miedzi o temperaturze 15C ogrzano do temperatury 308K.Wymagało to dostarczenia 22,8kj.oblicz masę miedzi
Dane:
t1=15C
t2=308K=35C
t=35C-15C=20C
Q=22,8kJ=22800J
Q=m*Cw*t
m=Q/Cw*t
m=22800J / 380J/kg*C * 20C = 3kg
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Dane:
t1=15C
t2=308K=35C
t=35C-15C=20C
Q=22,8kJ=22800J
Q=m*Cw*t
m=Q/Cw*t
m=22800J / 380J/kg*C * 20C = 3kg