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m = 1 kg
to = 20°C
c = 4200 J/kg °C
Ditanyakan : t₁ (to + Δt)
Penyelesaian : Δt = Q : (m . c)
= 84000 : (1 . 4200)
= 84000 : 4200
= 20°C
t₁ = to + Δt
= 20°C + 20°C
= 40°C