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m = 0,1 kg
ΔT = 5 C
Q = m. c. ΔT
210 = 0,1 . c . 5
210 = 0,5 c
420 = c
segitu kalor jenis nya
Q= 210 J
m= 0,1 kg
Δt= 5°C
Dit:
C=..?
Penye:
C= Q/m/Δt
C= 210/0,1/5
C= 420 J/kg°C