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Q=31,5 kj
m=1,2 kg
t1=-15°C
c=2.100 j
ditanya: t2....?
jawab:
Q=m.c.∆t
31.500 =1,2 x 2.100 x ∆t
31.500 = 2.520 x ∆t
∆t = 12,5
t2= 12,5-(-15) = 27,5°C