pH = 2 + log 2
= - log [H+]
= - log [-2 . 10^-2]
[H+] = -2 . 10^-2
Maaf kalau salah yaa:)
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pH = 2 + log 2
= - log [H+]
= - log [-2 . 10^-2]
[H+] = -2 . 10^-2
Maaf kalau salah yaa:)