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[L] [T]⁻² = ( ([L] [T]⁻¹)² - ([L] [T]⁻¹)² ) / 2[L]
[L] [T]⁻² = [L]² [T]⁻² / [L]
[L] [T]⁻² = [L] [T]⁻²
rumus diatas terbukti benar berdasarkan dimensinya
b) S = v₀t - 1/2at²
[L] = [L] [T]⁻¹ [T] - [L] [T]⁻² [T]²
[L] = [L] - [L]
[L] = [L]
rumus diatas terbukti benar berdasarkan dimensinya
3) F = G Mm / r²
[M] [L] [T]⁻² = G [M]² [L]⁻²
G = [M] [L] [T]⁻² . [M]⁻² [L]²
G = [M]⁻¹ [L]³ [T]⁻² => DIMENSINYA
G = m³/kg.s² = N m²/kg² => Satuannya
4. X = At² + Bt + C
a) At² = X
A [T]² = [L]
A = [L] [T]⁻²
Bt = X
B [T] = [L]
B = [L] [T]⁻¹
b) A = [L] [T]⁻² => m/s²
B = [L] [T]⁻¹ => m/s