Question

KAKA" TOLONG DONG JAWABANNYA 2 SOAL LAGI NIH PLIISS :'( :'(
*Sederhanakan bentuk pangkat berikut
a. (9 per 4)³
b. 12a³ - 6a per 2a²
*Rasionalkan bentuk akar :
3 per 3+√2

Answer 1

A) (9/4)³ = (3²/2²)³
= 3^6 / 2^6
= (3/2)^6
b) 12a³ - 6a
---------------
2a²
= 6a(2a² - 1)
---------------
2a . a
= 3(2a² - 1)
---------------
a
c) 3 / 3+√2
= (3 / 3+√2)(3-√2/3-√2)
= (3 . 3-√2)/(3+√2 . 3-√2)
={3(3-√2)}/ (9 - 2)
= 3(3-√2)
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7