Kaka ini gimana yaaaa. pakai caranya yah ka makasih banyak :)
RonaldRobi
![\displaystyle 2.)\ R= \sqrt{ 5^{2} + 13^{2} } \\ = \sqrt{25+169} \\ = \sqrt{194} \\ = \boxed{\boxed{13,92\ N}} \\ \\ 3.)\ Rumus\ dimensi\ Ek = [M].([L].[T]^{-1} )^2 \\ = [M].[L]^2.[T]^{-2} \\ Rumus\ dimensi\ W = [M].[L].[T] ^{-2} . [L] \\ = [M].[L] ^{2} .[T] ^{-2} \\ \\ Jadi\ , Hubungannya\ adalah \\ sama\ sama\ mempunyai\ satuan\ yang\ sama](https://tex.z-dn.net/?f=%5Cdisplaystyle+2.%29%5C+R%3D++%5Csqrt%7B+5%5E%7B2%7D+%2B+13%5E%7B2%7D+%7D++%5C%5C+%3D++%5Csqrt%7B25%2B169%7D++%5C%5C+%3D++%5Csqrt%7B194%7D++%5C%5C+%3D+%5Cboxed%7B%5Cboxed%7B13%2C92%5C+N%7D%7D+%5C%5C++%5C%5C+3.%29%5C+Rumus%5C+dimensi%5C+Ek+%3D+%5BM%5D.%28%5BL%5D.%5BT%5D%5E%7B-1%7D+%29%5E2+%5C%5C+%3D+%5BM%5D.%5BL%5D%5E2.%5BT%5D%5E%7B-2%7D++%5C%5C+Rumus%5C+dimensi%5C+W+%3D+%5BM%5D.%5BL%5D.%5BT%5D+%5E%7B-2%7D+.+%5BL%5D+%5C%5C+%3D+%5BM%5D.%5BL%5D+%5E%7B2%7D+.%5BT%5D+%5E%7B-2%7D++%5C%5C++%5C%5C+Jadi%5C+%2C+Hubungannya%5C+adalah+%5C%5C++sama%5C+sama%5C+mempunyai%5C+satuan%5C+yang%5C+sama "\displaystyle 2.)\ R= \sqrt{ 5^{2} + 13^{2} } \\ = \sqrt{25+169} \\ = \sqrt{194} \\ = \boxed{\boxed{13,92\ N}} \\ \\ 3.)\ Rumus\ dimensi\ Ek = [M].([L].[T]^{-1} )^2 \\ = [M].[L]^2.[T]^{-2} \\ Rumus\ dimensi\ W = [M].[L].[T] ^{-2} . [L] \\ = [M].[L] ^{2} .[T] ^{-2} \\ \\ Jadi\ , Hubungannya\ adalah \\ sama\ sama\ mempunyai\ satuan\ yang\ sama")
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