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Verified answer
A) fogoh(x)cari goh(x) dulu
goh(x) = g(h(x)) = √(x-1)
fog(h(x)) = f(g(h(x))) = f(√(x-1)) = {√(x-1)} - 1
b) goh(x) = (³√x) / (³√x)-1
fogoh(x) = √{(³√x) / (³√x)-1}
Verified answer
Bab Fungsi KomposisiMatematika SMA Kelas X
a] fogoh (x) = fog (x - 1)
= f(√(x - 1))
= (√(x - 1)) - 1
b] fogoh (x) = fog (∛x)
= f ((∛x)/((∛x) - 1)
= √((∛x) / ((∛x) - 1))