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Verified answer
Jawab₀¹∫ x√(x² +9) dx
u = x² +9
du = 2x dx
x dx = 1/2 du
batas integral
u = x² + 9
x =0 , u = 9
x = 1 , u = 10
₉¹⁰∫ 1/2 u^(1/2) du =
= [1/2 (2/3) U^(3/2) ]¹⁰₉
= 1/3 [u √u ]¹⁰₉
= 1/3 (10√10 - 9√9)
= 1/3 (10√10 - 27)