Diketahui :
Ditanyakan :
Jawab :
1. Kuat arus
[tex]\displaystyle Q = I\times t\\\\I = \frac{Q}{t}\\\\I = \frac{n\times e}{t}\\\\I = \frac{10^{20}\times 1,6\times 10^{-19}}{4}\\\\I = \frac{1,6\times10}{4}\\\\I = 4 \text{ Amphere}[/tex]
2. Beda potensial
[tex]\displaystyle V = I\times R\\\\V = 4 \times 20\\\\V = 80 \text{ Volt}[/tex]
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Verified answer
Pembahasan :
Diketahui :
Ditanyakan :
Jawab :
1. Kuat arus
[tex]\displaystyle Q = I\times t\\\\I = \frac{Q}{t}\\\\I = \frac{n\times e}{t}\\\\I = \frac{10^{20}\times 1,6\times 10^{-19}}{4}\\\\I = \frac{1,6\times10}{4}\\\\I = 4 \text{ Amphere}[/tex]
2. Beda potensial
[tex]\displaystyle V = I\times R\\\\V = 4 \times 20\\\\V = 80 \text{ Volt}[/tex]