Question

Kak ssoal integral lagi

Answer 1

Verified answer

Integral Substitusi.

∫ x² sin (x³ + 5) cos⁹ (x³ + 5) dx
u = cos (x³ + 5)
du / dx = -3x² sin (x³ + 5)
= ∫ x² sin (x³ + 5) u⁹ du / [-3x² sin (x³ + 5)]
= -1/3 ∫ u⁹ du
= -1/3 (1/10 u¹⁰) + C
= -1/30 cos¹⁰ (x³ + 5) + C