Question

Kak plus tolong jawab soal ini!!!!

Answer 1

∛3ˣ⁺² = 1/√27¹⁻ˣ

=> ∛3ˣ⁺² = (√27¹⁻ˣ)⁻¹ **ingat bahwa 1/x¹ = x⁻¹**

=> ∛3ˣ⁺² = √27ˣ⁻¹ **ingat bahwa (xᵃ)ᵇ = xᵃᵇ**

=> 3⁽ˣ⁺²⁾/³ = 27⁽ˣ⁻¹⁾/² **ingat bahwa ∛ = ¹/³ dan √ = ¹/²**

=> 3⁽ˣ⁺²⁾/³ = 3³⁽ˣ⁻¹⁾/²

=> 3⁽ˣ⁺²⁾/³ = 3⁽³ˣ⁻³⁾/²

=> (x + 2)/3 = (3x - 3)/2 **kalikan 6 semua**

=> 2(x + 2) = 3(3x - 3)

=> 2x + 4 = 9x - 9

=> 9x - 2x = 4 + 9

=> 7x = 13

=> x = 13/7