Jawaban:
3. (V11+V3)(V22-V6)=V11(V22-V6) +V3(V22-V6)
= V232-V66+V66-V18
= 11V2-3V2=8V2
5.
[tex] {x}^{ - \frac{2}{3} } . {y}^{ \frac{4}{3} } = {216}^{ - \frac{2}{3} } . {64}^{ \frac{4}{3} } = {6}^{3. - \frac{2}{3} } . {4}^{3. \frac{4}{3} } = {6}^{ - 2} . {4}^{4} = \frac{1}{ {6}^{2} } . {4}^{4} = \frac{1}{36} .256 = \frac{256}{36} = \frac{64}{9} [/tex]
7. c. pembilangnya sudah rasional
h.
[tex] \frac{2 \sqrt{5} + \sqrt{3} }{ \sqrt{15} } . \frac{ \sqrt{15} }{ \sqrt{15} } = \frac{2 \sqrt{75} + \sqrt{45} }{15} = \frac{10 \sqrt{3} + 3 \sqrt{5} }{15} [/tex]
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Jawaban:
3. (V11+V3)(V22-V6)=V11(V22-V6) +V3(V22-V6)
= V232-V66+V66-V18
= 11V2-3V2=8V2
5.
[tex] {x}^{ - \frac{2}{3} } . {y}^{ \frac{4}{3} } = {216}^{ - \frac{2}{3} } . {64}^{ \frac{4}{3} } = {6}^{3. - \frac{2}{3} } . {4}^{3. \frac{4}{3} } = {6}^{ - 2} . {4}^{4} = \frac{1}{ {6}^{2} } . {4}^{4} = \frac{1}{36} .256 = \frac{256}{36} = \frac{64}{9} [/tex]
7. c. pembilangnya sudah rasional
h.
[tex] \frac{2 \sqrt{5} + \sqrt{3} }{ \sqrt{15} } . \frac{ \sqrt{15} }{ \sqrt{15} } = \frac{2 \sqrt{75} + \sqrt{45} }{15} = \frac{10 \sqrt{3} + 3 \sqrt{5} }{15} [/tex]