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y-y1. x-x1
-------= --------
y2-y1. x2-x1
y-0. x-6
------=-------
2-0. 0-6
y. x-6
-----=------
2 -6
-6y=2(x-6)
-6y=2x-12
2x+6y-24=0 -----> m1= -2/6 = -1/3
garis h tegak lurus garis pertama, maka m1•m2=-1 ---> m2=3 dan melalui (4,0)
per.garisnya adalah
y-y1 = m(x-x1)
y-0= 3 (x-4)
y = 3(x-4)
y = 3x-12
y-3x+12=0 (D)