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u = 2x
du = 2 dx, sehingga dx = 1/2 du
Menyebabkan:
∫ sin 2x dx = ∫ sin u (1/2 du)
∫ sin 2x dx = ∫ 1/2 sin u du
∫ sin 2x dx = -1/2 cos u + C
Substitusikan kembali, diperoleh:
∫ sin 2x dx = -1/2 cos 2x + C