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v = kecepatan
t = waktu tempuh
paman Hadi
t1 = 15 menit = 0,25 jam
v1 = 48 km/jam
s1 = ( v1 × t ) + ( v1 × t1 )
s1 = ( 48 × t ) + ( 48 × 0,25 )
s1 = 48 t + 12
Beni
v2 = 52 km/jam
s2 = v2 × t
s2 = 52 × t
s2 = 52 t
jarak rumah paman Hadi dan rumah Beni
s = 87 km
s = s1 + s2
87 = 48 t + 12 + 52 t
87 - 12 = 48 t + 52 t
75 = 100t
t = 75/100
jarak yg di tempuh Beni
s2 = 52 t ----> t = 75/100
s2 = 52 × 75/100
s2 = 39 km
jawaban nya : C. 39,00 km